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If I have 4.5 moles of a gas at a pressure of 5.6 at and a volume of 12 L, what is the gas's temperature?

User Crissal
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Answer:

We can use the Ideal Gas Law equation to solve this problem:

PV = nRT

where:

P = pressure = 5.6 atm

V = volume = 12 L

n = moles = 4.5 mol

R = gas constant = 0.08206 L·atm/mol·K (assuming temperature is in Kelvin)

T = temperature (in Kelvin)

We want to solve for T, so we can rearrange the equation to isolate T:

T = PV/nR

Substituting the given values:

T = (5.6 atm)(12 L)/(4.5 mol)(0.08206 L·atm/mol·K)

T = 308.5 K

Therefore, the temperature of the gas is 308.5 Kelvin.

User Cdeterman
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