Answer:
We can use the Ideal Gas Law equation to solve this problem:
PV = nRT
where:
P = pressure = 5.6 atm
V = volume = 12 L
n = moles = 4.5 mol
R = gas constant = 0.08206 L·atm/mol·K (assuming temperature is in Kelvin)
T = temperature (in Kelvin)
We want to solve for T, so we can rearrange the equation to isolate T:
T = PV/nR
Substituting the given values:
T = (5.6 atm)(12 L)/(4.5 mol)(0.08206 L·atm/mol·K)
T = 308.5 K
Therefore, the temperature of the gas is 308.5 Kelvin.