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5. If I have 6.7 moles of a gas at a pressure of 0.090 atm and a temperature of 56.0 °C, what is the gas's volume?

User Xardas
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Answer:

We can use the ideal gas law to solve for the volume:

PV = nRT

where:

P = pressure = 0.090 atm

V = volume (unknown)

n = moles = 6.7 mol

R = gas constant = 0.08206 L·atm/mol·K

T = temperature = 56.0 + 273.15 = 329.15 K

Substituting the given values:

(0.090 atm) V = (6.7 mol) (0.08206 L·atm/mol·K) (329.15 K)

Simplifying:

V = (6.7 mol) (0.08206 L·atm/mol·K) (329.15 K) / (0.090 atm)

V = 164.0 L

Therefore, the gas has a volume of 164.0 L.

User SamVK
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