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(show work please) How many moles of neon gas are in 2 L tube that at 25 °c and 1.2 atm?​

User Ragulan
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Answer:

To calculate the number of moles of neon gas, we can use the ideal gas law equation:

PV = nRT

where:

P = pressure (in atm)

V = volume (in L)

n = number of moles

R = gas constant (0.0821 L·atm/mol·K)

T = temperature (in K)

We need to convert the given temperature from Celsius to Kelvin by adding 273.15:

25 °C + 273.15 = 298.15 K

Now we can plug in the values and solve for n:

(1.2 atm) (2 L) = n (0.0821 L·atm/mol·K) (298.15 K)

Simplifying the equation:

n = (1.2 atm x 2 L) / (0.0821 L·atm/mol·K x 298.15 K)

n = 0.097 mol

Therefore, there are 0.097 moles of neon gas in a 2 L tube at 25 °C and 1.2 atm.

User TongChen
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