Question

a spring has a spring constant of 80 N/m. How much elastic potential energy is stored in the spring when it is compressed by 0.1m?

Answer 1

The elastic potential energy stored in a spring can be calculated using the formula:

E = (1/2) kx^2

where E is the elastic potential energy, k is the spring constant, and x is the displacement of the spring from its equilibrium position.

Plugging in the given values, we get:

E = (1/2) (80 N/m) (0.1 m)^2

E = (1/2) (80 N/m) (0.01 m^2)

E = 0.4 J

Therefore, the elastic potential energy stored in the spring when it is compressed by 0.1m is 0.4 J.