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Look at the standard equation of the circle. (x − a)² + (y−b)² = r² If a circle has a center at (0, -5) and a diameter of 6 units, what are the values of a, b, and, r? Enter the value in each box.​

User Billa
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Answer:

a = 0

b = -5

r = 3

Explanation:

Given that the center of the circle is at (0, -5) and the diameter of the circle is 6 units, we can determine the values of a, b, and r for the standard equation of a circle: (x - a)^2 + (y - b)^2 = r^2.

a: The x-coordinate of the center of the circle, which is 0 in this case.

b: The y-coordinate of the center of the circle, which is -5 in this case.

r: The radius of the circle, which is half of the diameter. So, r = 6/2 = 3 units.

Therefore, the values for a, b, and r are:

a = 0

b = -5

r = 3

User Mitsuaki Ishimoto
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