Answer:
ML=14, KL=14, EL=6, MK=25.3
Explanation:
We can solve this using the properties of rhombuses:
ML and KL are the sides of a rhombus, and we know that in a rhombus, all 4 sides are the same. Given the value of 1 size, JK=14, we can determine the other 3 sides ML, KL and MJ, would all be equal to 14.
We also see that JL is the diagonal of the rhombus, and we know that JE is half the diagonal, so the other half, EL must be 6 aswell.
We can solve for MK using the pythagorean theorem.
We see that triangle KEL is a right angled triangle
If EL=6, and KL is 14, using a²+b²=c², KE would be equal to 12.65
KE is also half of MK, so MK would be equal to 12.65×2, which is 25.3
Hope this helps!