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Determine the equation of the circle with center ( − 7 , − 4 ) (−7,−4) containing the point ( − 1 , − 8 ) (−1,−8).

User Poidar
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Answer: The equation of the circle with center (-7, -4) containing the point (-1, -8) is (x + 7)^2 + (y + 4)^2 = 52.

Step-by-step explanation: The equation of a circle with center (h, k) and radius r is given by:

(x - h)^2 + (y - k)^2 = r^2

In this case, we are given the center (-7, -4) and a point on the circle (-1, -8). We can use the distance formula to find the radius:

r = sqrt((x2 - x1)^2 + (y2 - y1)^2)

= sqrt((-1 - (-7))^2 + (-8 - (-4))^2)

= sqrt(36 + 16)

= sqrt(52)

= 2sqrt(13)

Now we can substitute the values into the equation of a circle:

(x - (-7))^2 + (y - (-4))^2 = (2sqrt(13))^2

Simplifying:

(x + 7)^2 + (y + 4)^2 = 52

Therefore, the equation of the circle with center (-7, -4) containing the point (-1, -8) is (x + 7)^2 + (y + 4)^2 = 52.

User Robin Van Dijke
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