Question

PLEASE help solving these 2 problems

Answer 1

42° and 95°

Explanation:

1

the inscribed angle EFD is half the measure of its intercepted arc , that is

∠ EFD =
`(1)/(2)` × DE =
`(1)/(2)` × 84° = 42°

2

ABCD is a cyclic quadrilateral.

the opposite angles sum to 180° , that is

∠ B + ∠ D = 180°

∠ B + 85° = 180° ( subtract 85° from both sides )

∠ B = 95°