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In 5.8 moles of sucrose (C12H22O11) sample,

(i) Calculate the number of moles of sucrose (C12H22O11) in the above sample. [Note the Avogadro's constant: 6.02•10^23 atoms]

(ii) Calculate the number of moles of carbon (C) in the above sample.

(iii) Calculate the total number of carbon atoms in the above sample.

1 Answer

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Answer:

(i) The molar mass of sucrose (C12H22O11) can be calculated by adding the molar masses of the individual atoms:

molar mass of C12H22O11 = 12 x 12.01 + 22 x 1.01 + 11 x 16.00 = 342.3 g/mol

To calculate the number of moles of sucrose in the sample, we divide the mass of the sample by the molar mass:

moles of sucrose = mass of sample / molar mass

moles of sucrose = 5.8 / 342.3

moles of sucrose = 0.0169 mol

Therefore, there are 0.0169 moles of sucrose in the sample.

(ii) To calculate the number of moles of carbon in the sample, we need to determine the number of moles of C atoms present in each molecule of sucrose. Sucrose contains 12 carbon atoms per molecule.

moles of carbon = moles of sucrose x number of carbon atoms per molecule

moles of carbon = 0.0169 x 12

moles of carbon = 0.203 mol

Therefore, there are 0.203 moles of carbon in the sample.

(iii) To calculate the total number of carbon atoms in the sample, we multiply the number of moles of carbon by Avogadro's constant:

number of carbon atoms = moles of carbon x Avogadro's constant

number of carbon atoms = 0.203 x 6.02 x 10^23

number of carbon atoms = 1.22 x 10^23

Therefore, there are approximately 1.22 x 10^23 carbon atoms in the sample of sucrose.

Step-by-step explanation:

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