Question

Aaron, Bob and Casper had some marbles. Aaron had ⅙ of the marbles. Bob had 6 marbles more than Aaron. Casper had 18 marbles. How many marbles did they have altogether?​

Answer 1

Answer:If Aaron had ⅙ of the marbles, then Bob had (1/6 + 1/6) + 6 = 2/6 + 6 = 8/3 of the marbles.

Answer:If Aaron had ⅙ of the marbles, then Bob had (1/6 + 1/6) + 6 = 2/6 + 6 = 8/3 of the marbles.Together, Aaron and Bob had 1/6 + 8/3 = 17/6 of the marbles.

Answer:If Aaron had ⅙ of the marbles, then Bob had (1/6 + 1/6) + 6 = 2/6 + 6 = 8/3 of the marbles.Together, Aaron and Bob had 1/6 + 8/3 = 17/6 of the marbles.Adding Casper's 18 marbles, they had a total of 17/6 + 18 = 50/3 marbles.

Answer:If Aaron had ⅙ of the marbles, then Bob had (1/6 + 1/6) + 6 = 2/6 + 6 = 8/3 of the marbles.Together, Aaron and Bob had 1/6 + 8/3 = 17/6 of the marbles.Adding Casper's 18 marbles, they had a total of 17/6 + 18 = 50/3 marbles.Converting to a mixed number, they had 16 2/3 marbles altogether.