Answer:
Let's call the price of one adult ticket "a" and the price of one student ticket "s".
From the information given, we can set up two equations:
2a + 8s = 140 (equation 1)
5a + 8s = 182 (equation 2)
We can solve this system of equations using elimination or substitution.
Let's use elimination. We'll start by multiplying equation 1 by 5 and equation 2 by -2:
10a + 40s = 700 (equation 1, multiplied by 5)
-10a - 16s = -364 (equation 2, multiplied by -2)
Adding these two equations eliminates the "a" term:
24s = 336
Dividing both sides by 24:
s = 14
Now we can substitute this value of "s" into either equation to solve for "a". Let's use equation 1:
2a + 8(14) = 140
2a + 112 = 140
2a = 28
a = 14
So the price of one adult ticket is $14 and the price of one student ticket is