Question

The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.59 m and 1.00 m, respectively. The respective rotational speeds are 448 rev/min and 4,140 rev/min. Calculate the speeds of the tips of both rotors.

Answer 1

$\sf\textbf{Tip\:speed\:of\: main\:rotor}\:\:=\:\pi \times$

$\sf\textbf{diameter\:of\:main\:rotor} \times {rotational\: speed\:of main\:rotor}$

$\implies\sf\textbf\:=\:\pi \times 7.59\:{ m} \times 448\:{\:rev/min}$

$\implies\sf\textbf\:=\:10,676.68\:{\:m/min}$

$\sf\textbf\:{Tip\:speed\:of\:tail\:rotor}\:=\:\pi \times$

$\sf\textbf\:{diameter\:of\:tail\:rotor} \times\:{rotational\:speed\:of\:tail\:rotor}$

$\implies\sf\textbf\:=\:\pi \times 1.00\:{ m} \times 4140\:{\:rev/min}$

$\implies\red\bigstar{\boxed{\textsf{\textbf{\:=\:13,015.93 \text{ m/min}}}}}$

`\huge{\colorbox{black}{\textcolor{lime}{\textsf{\textbf{I\:hope\:this\:helps\:!}}}}}`

`\begin{align}\colorbox{black}{\textcolor{white}{\underline{\underline{\sf{Please\: mark\: as\: brillinest !}}}}}\end{align}`

`\textcolor{blue}{\small\textit{If you have any further questions, feel free to ask!}}`

`{\bigstar{\underline{\boxed{\sf{\textbf{\color{red}{Sumit\:Roy}}}}}}}\\`