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Find the molar solubility of SrCO3 in pure water. (Ksp = 5.4 x 10-10).

User Foobnix
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Molar solubility of SrCO3 is 2.3 x 10^-5
Find the molar solubility of SrCO3 in pure water. (Ksp = 5.4 x 10-10).-example-1
User Ivan Sopov
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Answer: 7.35 x 10^-5.

Explanation: Easy. The precipitate equation is SrCO3 --> Sr2+ and Co32-. For every 1 mole of SrCo3, 1 mole of Sr2+ and 1 mole of Co32- is formed. Hence, the equation would be Q = [Sr2+][CO3 2-], where it is 5.4 x. 10 ^-10 = x(x). 5.4 x. 10 ^-10 = x^2. Solve for x. X is 7.35 x 10^-5.

Molar solubility by definition is the number of moles of a solute that can be dissolved per liter of solution before the solution becomes saturated. When Q > Ksp, precipitate forms as it is super saturated, and when Q < Ksp, precipitate would not form. When Q = Ksp, it is at equilibrium.

User Raja Selvaraj
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