Question

PLEASE HELP!!!

Find the tangent of the larger acute angle in a right triangle with side lengths 9, 12, and 15.
Tangent of the larger acute angle:

Answer 1

Explanation:

remember, tan(x) = sin(x)/cos(x)

the larger angle is between the 9 and 15 sides, as in a right-angled triangle the Hypotenuse (the side opposite of the 90° angle) is the longest side in the triangle.

and the bigger the acute angle the bigger the opposite side.

for this

12 = sine × 15

9 = cosine × 15

tangent = sine×15 / (cosine×15) = 12/9 = 4/3