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find three mixed numbers so that the sum is 18 and the difference between the greatest number and the least number is 5 1/5

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Answer:

Explanation:

Let's begin by assigning variables to represent the three mixed numbers. Let a be the greatest mixed number, b be the middle mixed number, and c be the least mixed number. Then we can write:

a + b + c = 18 (the sum of the three mixed numbers is 18)

a - c = 5 1/5 (the difference between the greatest and least mixed numbers is 5 1/5)

To solve for a, b, and c, we can use substitution. From the second equation, we can solve for a in terms of c:

a = c + 5 1/5

Substituting this expression for a into the first equation, we get:

(c + 5 1/5) + b + c = 18

Simplifying, we get:

2c + b = 12 4/5

Now we need to find three mixed numbers that satisfy this equation. We can start by choosing a value for c. Let's choose c = 2 1/2, which is the smallest possible value for c that will allow the mixed numbers to be non-negative. Then we can solve for b:

2c + b = 12 4/5

2(2 1/2) + b = 12 4/5

5 + b = 12 4/5

b = 7 4/5

Finally, we can solve for a using the equation a = c + 5 1/5:

a = c + 5 1/5

a = 2 1/2 + 5 1/5

a = 7 3/5

Therefore, three mixed numbers that satisfy the conditions of the problem are:

The greatest mixed number: 7 3/5

The middle mixed number: 7 4/5

The least mixed number: 2 1/2

And indeed, their sum is 18 and the difference between the greatest and least mixed numbers is 5 1/5.

User Josh KG
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