Final answer:
The argument is shown to be valid through a series of logical inferences applying modus tollens, modus ponens, and disjunctive syllogism, leading to the conclusion that if q then r must be true.
Step-by-step explanation:
To show that the argument form with premises (p ∧ t) → (r∨s), q→(u∧t), u→p, and ¬ s and the conclusion q → r is valid, we need to use rules of inference and the fact that if an argument with additional premise q and conclusion r is valid, then the argument with conclusion q → r is also valid.
From the premise ¬ s and (p ∧ t) → (r∨s), we can apply modus tollens to infer ¬(p ∧ t).
Given u→p, we apply modus ponens with the premise u (from q→(u∧t) assuming q) to infer p.
Since we have ¬(p ∧ t) from step 1 and p from step 2, we can deduce that ¬ t must be true.
Now that we have q implies both u and ¬ t (from steps 1 and 3), but since we also have u → p, we know p must be true. Therefore, from q we have p and ¬t.
Finally, given (p ∧ t) → (r∨s) and knowing that s is false, r must be true if p and t are both true. But since t is not true, p alone guarantees r. Therefore, if q then r, validating the conclusion q → r.