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HELPPPP FASTTTTTTT

An inflated balloon is left outside overnight. It has a volume of 1.7 4 L when the temperature is 20.2 degC and the pressure is 1.02 atm. At what temperature will the balloon have a volume of 1.56 L if the pressure falls to 0.980 atm?

What gas law will you use to solve this problem?
options
A. boyles gas law
B. charles gas law
C. Gay lussacs gas law
D. combined gas law
E. ideal gas law
What is your reason for choosing the gas law?
options
A.moles are in the problem
B. there are 2 variables that are changing
C. there are 3 variables that are changing
In this problem, is the volume increasing or decreasing?
What is the unknown that you are solving for?
options.
A.T1
B.T2
What temperature will you use in your calculations?
A. 20.2 degc
B. 273 k
C. 293.2 K
What is the final temperature after the volume and pressure decrease in this problem?
options.
A. 253k
B. 314k
C. 353 K

1 Answer

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Step-by-step explanation:

1.The gas law that we will use to solve this problem is the combined gas law.

2.We will choose the combined gas law because there are three variables that are changing in this problem: volume, pressure, and temperature.

3The volume is decreasing in this problem, from 1.74 L to 1.56 L.

The unknown that we are solving for is T2, the temperature at which the balloon will have a volume of 1.56 L.

4We will use the temperature in Kelvin for our calculations. To convert from Celsius to Kelvin, we add 273.15 to the Celsius temperature. Therefore, the temperature we will use in our calculations is 293.35 K (20.2°C + 273.15).

5To find the final temperature, we can use the combined gas law equation:

(P1 x V1)/T1 = (P2 x V2)/T2

where P1 = 1.02 atm, V1 = 1.74 L, T1 = 293.35 K, P2 = 0.980 atm, and V2 = 1.56 L.

Substituting the values into the equation and solving for T2, we get:

T2 = (P2 x V2 x T1)/(P1 x V1)

= (0.980 atm x 1.56 L x 293.35 K)/(1.02 atm x 1.74 L)

= 268.06 K

Therefore, the final temperature after the volume and pressure decrease is 268.06 K, which is approximately 253 K (option A).

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