Question

Mike bought a total of 50 tickets that costed $29. If the ride tickets were 70cents and the game tickets were 50 cents how many ride tickets did he buy

Answer 1

• Mike bought 20 ride tickets.

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Let r be the number of ride tickets Mike bought and g be the number of game tickets.

From the problem, we know that:

• r + g = 50 (because he bought a total of 50 tickets)

And we also know that:

• 0.70r + 0.50g = 29 (because the ride tickets cost 70 cents and the game tickets cost 50 cents, and he spent a total of $29).

Let's first simplify the second equation, by multiplying both sides by 100 to get rid of decimals:

• 70r + 50g = 2900

Now we can use the first equation to solve for g in terms of r:

• g = 50 - r

We can substitute this into the second equation:

• 70r + 50(50 - r) = 2900
• 70r + 2500 - 50r = 2900
• 20r = 400
• r = 20

So Mike bought 20 ride tickets.