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A ball is launched from a 273.28-foot tall platform. the equation for the balls height h at time T seconds after launch is h(t)=-16t^2+52.8t+273.28, where h is in feet. At what time does the ball achieve it’s maximum height

User Phong Vo
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1 Answer

1 vote

Answer:

4 seconds

Explanation:

User CircuitBurn
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