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How many atoms of Kr (Krypton) are in a balloon that contains 2.00 mol of Kr? (4)

User Bnuhero
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1 Answer

6 votes

Answer:


atoms= 1.204x10^(24)atoms

Step-by-step explanation:

Hello!

In this case, according to the Avogadro's number, it is possible to compute the atoms of Kr in 2.00 moles as shown below:


atoms=2.00mol*(6.022x10^(23)atoms)/(1mol) \\\\atoms= 1.204x10^(24)atoms

Best regards!

User Mvlupan
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