Question

What are the zeros of f(x) = x² - 10x+25?

OA. x= -5 and x = 5
O B. x = 5 only
OC. x = -5 and x = 10
O D. x = -5 only
ANSWER ASAP

Answer 1

Explanation:

x² - 10x+25 = (x - 5)(x + 5)

If U want to do this U have to know (ax+b)(cx+d) = acx² + (bc+ad)x + bd

and how to use this and the quadratic formula to get your values. Although some people just know the values because of familiarity.

If set equal to zero we get

(x - 5)(x + 5) = 0

Therefore if x = 5 we get (5-5)(5+5) = (0)(5) = 0

And we have if x = -5, then (-5-5)(5-5) = (-10)(0) = 0

So our x-values should be 5 & -5

Which would be OA.

Answer 2

B

Explanation:

We can find the zeros of the quadratic function f(x) = x² - 10x + 25 by setting f(x) equal to zero and solving for x:

x² - 10x + 25 = 0

This quadratic equation can be factored as:

(x - 5)² = 0

Using the zero product property, we can see that this equation is true when:

x - 5 = 0

So the only zero of f(x) is x = 5.

Therefore, the correct answer is option B: x = 5 only.