Question

Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will form, enter its empirical formula in the last column. Does a precipitate form when A and B empirical formula of solution A solution B precipitate are mixed? manganese(II) iodide zinc sulfate yes O no potassium chloride barium bromide O yes no olo zinc bromide sodium sulfide O yes O no

Answer 1

Yes, a precipitate forms when solutions A and B are mixed. The empirical formula of the precipitate is
`\( \text{ZnS} \)`.

Step-by-step explanation:

When solutions A and B are mixed, manganese(II) iodide is formed, and it is soluble in water. Thus, no precipitate is formed for the first pair.

For the second pair, when potassium chloride and barium bromide solutions are mixed, a precipitate is formed. The balanced chemical equation for this reaction is:

`\[ \text{2KCl(aq) + BaBr}_2(\text{aq}) \rightarrow \text{2KBr(aq) + BaCl}_2(\text{s}) \]`

Barium chloride
`(\( \text{BaCl}_2 \))` is a white precipitate that forms in this double replacement reaction.

Lastly, when zinc bromide and sodium sulfide solutions are mixed, a precipitate is formed. The balanced chemical equation is:

`\[ \text{ZnBr}_2(\text{aq}) + \text{Na}_2\text{S}(\text{aq}) \rightarrow \text{ZnS}(\text{s}) + \text{2NaBr}(\text{aq}) \]`

Zinc sulfide
`(\( \text{ZnS} \))` is the precipitate formed in this reaction.

In summary, a precipitate is formed in the second and third pairs, and their empirical formulas are
`\( \text{BaCl}_2 \) and \( \text{ZnS} \)` respectively. These conclusions are based on the solubility rules, where chlorides are generally soluble except for those of silver, lead, and mercury(I), and sulfides are insoluble except for those of alkali metals and ammonium. The balancing of chemical equations helps confirm the stoichiometry of the reactions.

Answer 2

To determine if a precipitate forms when aqueous solutions A and B are mixed, we need to consider the solubility rules. By cross-combining the cations and anions of the solutions, we can determine if any potential products are insoluble and will form a precipitate.

Step-by-step explanation:

In order to determine whether a precipitate forms when aqueous solutions A and B are mixed, we need to consider the solubility rules. The solubility of ionic compounds depends on the combination of cations and anions. If the resulting product is insoluble, a precipitate will form. By cross-combining the cations and anions of solutions A and B, we can determine if any of the potential products are insoluble.

Let's look at the given combinations:

1. manganese(II) iodide and zinc sulfate: Manganese(II) iodide is insoluble, so a precipitate will form.
2. potassium chloride and barium bromide: Both potassium chloride and barium bromide are soluble, so no precipitate will form.
3. zinc bromide and sodium sulfide: Zinc bromide is soluble, but sodium sulfide is insoluble. Therefore, a precipitate of zinc sulfide will form.