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Given the following parameters, determine the correct sinusoidal equation for a sine wave: f=1kHz, A=2v, φ (phase angle)= -π radians

a. 1sin(2π5t - π)
b. 2sin(2π1000t - π)
c. 1sin(2π1000t)
d. 2sin(2π1t + π)

1 Answer

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The general equation for a sinusoidal wave is:

y = A sin(2πft + φ)

where A is the amplitude, f is the frequency, t is time, and φ is the phase angle.

Given the parameters f = 1 kHz, A = 2 V, and φ = -π radians, we can plug them into the general equation to get:

y = 2 sin(2π × 1 kHz × t - π)

Simplifying, we get:

y = 2 sin(2000πt - π)

Comparing the equation with the options given:

a. 1sin(2π5t - π) - This equation has a frequency of 5 Hz, not 1 kHz.

b. 2sin(2π1000t - π) - This equation matches the given parameters and is correct.

c. 1sin(2π1000t) - This equation has an amplitude of 1 V, not 2 V.

d. 2sin(2π1t + π) - This equation has a frequency of 1 Hz, not 1 kHz, and the phase angle is positive, not negative.

Therefore, the correct sinusoidal equation is:

y = 2 sin(2π × 1 kHz × t - π), which is option b.

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