Question

(Figure 1) is the potential-energy diagram for a 500 g particle that is released from rest at A . What is the particle's speed at B ?

Answer 1

Step-by-step explanation:

according to the graph at B the potential energy of the particle is 2J

therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.

`E_(k) =1/2mv^(2)`

2J= 1/2*1/2kg*v^2

8=v^2

v= 2√2 ms-1