Question

A line has a slope of -2 and passes through the point (-2, -3). Write its equation in slope-

intercept form.

Answer 1

The equation of the line in slope-intercept form is y = -2x - 7.

Step-by-step explanation:

The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.

Given that the slope of the line is -2 and it passes through the point (-2, -3), we can substitute the values into the equation and solve for the y-intercept:

-3 = -2(-2) + b

-3 = 4 + b

b = -7

Therefore, the equation of the line in slope-intercept form is y = -2x - 7.

Answer 2

The slope-intercept form of a line's equation is y = mx + b, where m is the slope of the line and b is the y-intercept. We can use the given slope and point to solve for the y-intercept and write the equation in slope-intercept form.

Given: Slope (m) = -2 and point (-2, -3)

• Step 1: Use the point-slope form of a line's equation to find the equation of the line in point-slope form:
• y - y1 = m(x - x1) (where x1,y1 are the coordinates of the given point)
• y - (-3) = -2(x - (-2))
• y + 3 = -2(x + 2)
• Step 2: Simplify the equation by distributing the -2:
• y + 3 = -2x - 4
• Step 3: Solve for y by subtracting 3 from both sides of the equation:
• y = -2x - 7

Therefore, the equation of the line in slope-intercept form is y = -2x - 7.