Answer:
the answer is (d) between -2 and -1.
Explanation:
To find the real zeros of f(x) = x³ - 2, we need to solve the equation f(x) = 0.
x³ - 2 = 0
x³ = 2
Taking the cube root of both sides, we get:
x = ∛2
Since ∛2 is irrational, it cannot be written exactly as a fraction or decimal. However, we can approximate it to any desired degree of accuracy using numerical methods.
Since ∛2 is positive, it follows that the real zeros of f(x) are located between -2 and -1, since f(x) is negative for x < -2, and f(x) is positive for x > -1. Therefore, the answer is (d) between -2 and -1.