Question

For each of the following scenarios, determine whether the calculated molarity would be too low, too high, or unaffected and explain why:

a. You added 1.0 g of zinc (instead of 0.3-0.4 g) to your unknown sample.
b. You added 50 mL DI (instead of 25mL) to your 10.00 mL unknown sample and then added the Zn.
c. The cooper was not completely dry before weighing.

Answer 1

In scenario a, the calculated molarity would be too high due to the addition of more zinc. In scenario b, the calculated molarity would be unaffected by the addition of more water. In scenario c, the calculated molarity would be unaffected by the dryness of the copper.

Step-by-step explanation:

In scenario a, where 1.0 g of zinc was added instead of 0.3-0.4 g, the calculated molarity would be too high. This is because adding more zinc than required would increase the number of moles of zinc in the solution, leading to a higher concentration of zinc ions.

In scenario b, where 50 mL DI water was added instead of 25 mL, the calculated molarity would be unaffected. This is because the volume of water does not affect the molarity as long as the amount of solute and solvent ratio remains the same.

In scenario c, where the copper was not completely dry before weighing, the calculated molarity would be unaffected. This is because the molarity calculation does not depend on the dryness of the copper, but rather on the number of moles of solute in a given volume of solvent.