Final answer:
The pH of a 3.1 × 10⁻⁴ M CSOH solution is 3.51.
Step-by-step explanation:
The pH of a solution can be determined using the formula: pH = -log [H3O+].
Given the concentration of the CSOH solution as 3.1 × 10⁻⁴ M, we can substitute this value into the formula.
pH = -log (3.1 × 10⁻⁴) = 3.51.
Therefore, the pH of the 3.1 × 10⁻⁴ M CSOH solution is 3.51.