Answer:
±√7 and ±√6
Explanation:
Let's denote x^2 as y, then the equation becomes:
y^2 - 6y - 7y - 6 = 0
y(y - 6) - 7(y - 6) = 0
(y - 7)(y - 6) = 0
Substituting back y with x^2, we get:
(x^2 - 7)(x^2 - 6) = 0
Solving each factor separately:
x^2 - 7 = 0 or x^2 - 6 = 0
x^2 = 7 or x^2 = 6
x = ±√7 or x = ±√6
Therefore, the zeroes of the equation are ±√7 and ±√6.