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What is the force on a 1,250 kg elevator that is in free fall at 9.8 m/s²? Ignore air

resistance, round your answer to the nearest tenth and use appropriate units.

1 Answer

1 vote

Answer:


\boxed{12250N}

Step-by-step explanation:

Assuming we disregard air resistance, the only force acting on the elevator will be its weight.


F \implies w=m\cdot g

where:


F= force


w= weight


m= mass → 1250kg


g= gravity acceleration → 9.8m/s^2

Then:


F= 1250kg \cdot 9.8m/s^2\\F=12250 kg\cdot m/s^2= 12250N

Hope it helps.


\text{-B$\mathfrak{randon}$VN}

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