Final answer:
The 0.1 M aqueous solution of Al(NO3)3 will have the lowest freezing point among the given options because it produces the most particles upon dissociation, leading to the most significant freezing point depression.
Step-by-step explanation:
The student is asking which 0.1 M aqueous solution will have the lowest freezing point among the given options. This question relates to colligative properties, specifically freezing point depression, which is affected by the number of solute particles in a solution. Freezing point depression occurs because the solute particles disrupt the formation of a solid structure, thereby lowering the freezing point of the solution.
Based on the given options, we must consider the number of particles each compound will produce in 0.1 M solution:
- NaCl dissociates into 2 ions (Na+ and Cl-).
- Al(NO3)3 dissociates into 4 ions (Al3+ and 3 NO3-).
- K2CrO4 dissociates into 3 ions (2 K+ and CrO4^2-).
- Na2SO4 dissociates into 3 ions (2 Na+ and SO4^2-).
- Sucrose does not dissociate; it remains as 1 molecule C12H22O11.
Because Al(NO3)3 dissociates into the most particles (four), a 0.1 M solution of this compound will have the lowest freezing point compared to the other options listed.