Question

In the xy-plane, what is the y-intercept of the graph of the equation y=6(x-1/2)(x+3)?

Answer 1

The y-intercept of the equation y=6(x-1/2)(x+3) is found by setting x=0 and solving for y, resulting in y=-9, which is the point where the graph intersects the y-axis.

Step-by-step explanation:

The y-intercept of the graph of the quadratic equation y=6(x-1/2)(x+3) is found by setting the value of x to zero. This y-intercept represents the point at which the graph intersects the y-axis. To find the y-intercept, we substitute x = 0 into the equation, giving us y = 6(0-1/2)(0+3). This simplifies to y = 6(-1/2)(3), which then simplifies to y = -9. Therefore, the y-intercept of the equation is y = -9.

Answer 2

The y-intercept of the graph of the equation is -9. This means that the graph crosses the y-axis at the point (0, -9).

Step-by-step explanation:

To solve this question, we need to plug in x = 0 into the given equation and simplify. We get:

y = 6(0 - 1/2)(0 + 3) y = 6(-1/2)(3) y = -9

Therefore, the y-intercept of the graph of the equation is -9. This means that the graph crosses the y-axis at the point (0, -9).