Answer:
Explanation:
To find when the ball reaches its maximum height, we need to find the vertex of the quadratic function h(t) = 76t - 16t^2.
The vertex of a quadratic function of the form y = ax^2 + bx + c is at the point (-b/2a, f(-b/2a)), where f(x) = ax^2 + bx + c.
In this case, a = -16 and b = 76, so the time at which the ball reaches its maximum height is given by:
t = -b/2a = -76/(2*(-16)) = 2.375
Rounded to the nearest hundredth, the ball reaches its maximum height after 2.38 seconds (Option D).