Question

Calculate the decrease in temperature when 3.00 L at 28.0 °C is compressed to 1.00 L.

Answer 1

`\huge\boxed{\sf T_2=100.3 \ K}`

Step-by-step explanation:

Given data:

Volume 1 =
`V_1` = 3.00 L

Volume 2 =
`V_2` = 1.00 L

Temperature 1 =
`T_1` = 28 °C + 273 = 301 K

Required:

Temperature 2 =
`T_2` = ?

Formula:

`\displaystyle (V_1)/(T_1) = (V_2)/(T_2)` (Charles Law)

Solution:

Put the given data in the above formula.

`\displaystyle (3.00)/(301) = (1.00)/(T_2) \\\\Cross \ Multiply\\\\3 * T_2=301 * 1\\\\3T_2= 301\\\\Divide \ both \ sides \ by \ 3\\\\T_2=301/3\\\\T_2=100.3 \ K\\\\\rule[225]{225}{2}`