Question

How much heat, in joules, would be required to raise the temperature of 450 g of

Aluminum (c Al = 0.21 cal/g o C) from 19.5 o C to 31.2 o C?

Answer 1

`\huge\boxed{\sf Q = 1105.65\ cal}`

Step-by-step explanation:

Given data:

Mass = m = 450 g

T₁ = 19.5 °C

T₂ = 31.2 °C

Change in Temperature = ΔT = 31.2 - 19.5 = 11.7 °C

c = 0.21 cal/g °C

Required:

Heat = Q = ?

Formula:

Q = mcΔT

Solution:

Put the given data in the above formula.

Q = (450)(0.21)(11.7)

Q = 1105.65 cal

`\rule[225]{225}{2}`