Question

Use logb28
PLEASE HELP SOLVE!! 30 PTS!!

Answer 1

logb28 ≈ 1.634.

Explanation:

logb28 = (log428)/(log47)

We can then substitute the given values for logb4 and logb7:

logb28 = (log428)/(log47) = (log28)/(log24 + log27) = (log28)/(1.386 + 1.946)
1.386+1.946=3.332

logb28/3.332
logb28 ≈ 1.634.

Answer 2

• 
  `log_b28=3.332`

--------------------

Given:

• 
  `log_b 4 = 1.386\ and\ bog_b7=1.946`

Use the following identity to find
`log_b28`:

• 
  `log_a(bc)=log_ab+log_ac`

Apply the identity to the given:

• 
  `log_b28=log_b(4*7)=log_b4+log_b7=1.386+1.946=3.332`