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Find a vector v parallel to u = -4i + 3j + 6k and with a magnitude ||v|| = 4​

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Answer: To find a vector parallel to u = -4i + 3j + 6k and with magnitude ||v|| = 4, we can use the formula:

v = (||v|| / ||u||) u

where u is the given vector and ||u|| is its magnitude.

First, we find the magnitude of u:

||u|| = sqrt((-4)^2 + 3^2 + 6^2) = sqrt(61)

Then, we plug in the values to get:

v = (4 / sqrt(61)) (-4i + 3j + 6k)

Multiplying out, we get:

v = (-16/sqrt(61))i + (12/sqrt(61))j + (24/sqrt(61))k

Therefore, the vector v parallel to u = -4i + 3j + 6k and with a magnitude ||v|| = 4 is:

v = (-16/sqrt(61))i + (12/sqrt(61))j + (24/sqrt(61))k.

Explanation:

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