Answer:
m∠R=x=37°; m∠QOR=53°
Explanation:
Any line that is tangent to a circle (such as QR) is perpendicular to the circle's radius (QO). Therefore, ΔOQR is a right triangle, with the right angle at Q.
1. You can use 90 + (x+16) + x = 180 or (x+16) + x = 90 to solve for x.
2. If needed, you can then use the solution from step 1 to find the measure of ∠QOR.