168k views
2 votes
How many moles of a salute are needed to prepare 300 mL of 0.8 mm and NACL solution​

User Ambie
by
8.4k points

1 Answer

3 votes

Answer: 0.24 Moles. WARNING: "mm" in the original question seems to be a typo and was assumed to be "M" (moles per liter) for concentration.

Explanation:

To calculate the number of moles of solute needed to prepare a solution, we can use the formula:

moles of solute = concentration (in moles per liter) * volume of solution (in liters)

Given:

Concentration of NaCl solution = 0.8 M (moles per liter)

Volume of solution to be prepared = 300 mL = 300/1000 L (converted to liters)

Plugging in the given values:

Concentration = 0.8 M

Volume of solution = 300/1000 L

moles of NaCl = 0.8 M * 300/1000 L

Calculating:

moles of NaCl = 0.24 moles

So, 0.24 moles of NaCl are needed to prepare 300 mL of a 0.8 M NaCl solution.

User Jonhoare
by
8.4k points