Question

What is the vertex of the graph of the equation Y=3x2( to the second power) +6x+1

A.(-1,-2)
B.(-1, 10)
C.(1, -2)
D.(1, 10)

Answer 1

Answer: To find the vertex of the graph of the equation Y=3x^2+6x+1, we can use the formula:

x = -b/2a

where a = 3 and b = 6, which are the coefficients of the x^2 and x terms, respectively.

x = -6/(2 x 3) = -1

Substituting x = -1 into the equation, we get:

Y = 3(-1)^2 + 6(-1) + 1 = -2

Therefore, the vertex of the graph is (-1, -2), so the answer is A. (-1,-2).

Explanation: