Since Q is the midpoint of NP, we know that NQ = QP. Similarly, we know that RS is the midpoint of OP, so we have RS = SO.
Let's label the length of QS as x. Then, we know that QR = 2x and SR = 3x.
To find the perimeter of triangle NOP, we need to find the lengths of NO, OP, and NP.
Using the Pythagorean Theorem, we can find that:
NO^2 = NQ^2 + OQ^2
NO^2 = (QP)^2 + (SO)^2
NO^2 = (x)^2 + (2x)^2
NO^2 = 5x^2
NO = x√5
Similarly, we can find that:
OP^2 = OQ^2 + PQ^2
OP^2 = (SO)^2 + (QP)^2
OP^2 = (3x)^2 + (x)^2
OP^2 = 10x^2
OP = x√10
Finally, we know that NP = NO + OP, so:
NP = x√5 + x√10
NP = x(√5 + √10)
To find the perimeter of NOP, we add up the three sides:
Perimeter of NOP = NO + OP + NP
Perimeter of NOP = x√5 + x√10 + x(√5 + √10)
Perimeter of NOP = x(2√5 + 2√10)
Perimeter of NOP = 2x(√5 + √10)
We can substitute the value we found for QS, which is x, to get:
Perimeter of NOP = 2(5 + 2√10)
Perimeter of NOP = 10 + 4√10
Therefore, the perimeter of triangle NOP is 10 + 4√10 units.