Answer:
We can use the given formula to calculate the decibel level D when the intensity level I is 63,096 times Io:
D = 10log(I/lo)
Where Io is the reference intensity level and is typically taken to be the threshold of hearing, which is 10^−12 watts/m^2.
So, substituting the values, we get:
D = 10log(63,096*Io/Io) = 10log(63,096)
Using a calculator, we find:
D ≈ 47.1 dB
Rounding this to the nearest whole number, we get:
The decibel level is 47 dB when I is 63,096 times Io.
I hope this helps mate.