Question

I’ve had trouble on these even on my test and I still can’t figure it out. Can someone explain how to solve:

3x = y - 2
6x = 4 - 2y

Answer 1

Answer: Sure, here's how to solve the system of equations:

1. Start with the first equation: 3x = y - 2

Solve for y by adding 2 to both sides: y = 3x + 2

2. Substitute the value of y from the first equation into the second equation:

6x = 4 - 2y

6x = 4 - 2(3x + 2) (substitute y = 3x + 2)

6x = 4 - 6x - 4

12x = 0

3. Solve for x by dividing both sides by 12: x = 0

4. Substitute the value of x from step 3 into either equation to solve for y:

y = 3x + 2

y = 3(0) + 2

y = 2

Therefore, the solution to the system of equations is (x, y) = (0, 2).

hope this helpsss :D

Explanation: