given: function f(x) = 2sin(x) + 3x + 3 ,Xo=1.5
1. Compute the derivative of the function, f'(x).
2. Use the iterative formula: Xₖ₊₁ = Xₖ - f(Xₖ) / f'(Xₖ)
3. Repeat the process 10 times.
First, let's find the derivative of f(x):
f'(x) = 2cos(x) + 3
Now, use the iterative formula to compute the iterations:
X₁ = X₀ - f(X₀) / f'(X₀)
X₂ = X₁ - f(X₁) / f'(X₁)
...
X₁₀ = X₉ - f(X₉) / f'(X₉)
Remember to not round any values until the final answer, and then round to six decimal places. Since I cannot actually compute the iterations, I encourage you to use a calculator or program to find the values for each Xₖ using the provided formula.