Final answer:
To estimate f(2.05, 3.95), we use the function's value and its partial derivatives at the nearby point (2, 4) to compute the linear approximation. The estimated value turns out to be approximately 5.025.
Step-by-step explanation:
We can estimate the value of the function f(2.05, 3.95) using a linear approximation, which involves the function's value and its partial derivatives at a nearby point. Given that f(2, 4) = 5, fx(2,4) = 0.3, and fy(2,4) = -0.2, we can approximate the change in f as follows:
Δf ≈ fx(2,4) Δx + fy(2,4) Δy
Where Δx = 2.05 - 2 = 0.05 and Δy = 3.95 - 4 = -0.05.
So,
Δf ≈ (0.3)(0.05) + (-0.2)(-0.05)
Δf ≈ 0.015 + 0.01
Δf ≈ 0.025
Therefore, we estimate that:
f(2.05, 3.95) ≈ f(2, 4) + Δf ≈ 5 + 0.025 ≈ 5.025