Question

Solve the following system of equations:

x^2−y=4
y=3x
A. (4, 12), (-1, -3)
B. (-4, 12)
C. (-4, 12), (-1, -3)
D. (4, 12)

Answer 1

Substituting y = 3x from the second equation into the first equation gives:

x^2 - 3x - 4 = 0

We can factor the quadratic equation as:

(x - 4)(x + 1) = 0

This gives us two possible values of x:

x = 4 or x = -1

Substituting these values into the second equation, we get:

If x = 4, then y = 3x = 12, so (4, 12) is a solution.

If x = -1, then y = 3x = -3, so (-1, -3) is a solution.

Therefore, the solutions to the system of equations are (4, 12) and (-1, -3).

The answer is C. (-4, 12), (-1, -3) is not a correct option as -4 is not a solution to the system of equations.

Answer 2

Option A is correct

Explanation:

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