To calculate the amount of H2O produced from 50 g of NaOH, we need to first determine the limiting reagent in the reaction.
The balanced equation tells us that 2 moles of NaOH react with 1 mole of H2SO4 to produce 2 moles of H2O.
First, we need to convert 50 g of NaOH to moles:
50 g NaOH / 40.00 g/mol NaOH = 1.25 moles NaOH
Next, we need to convert moles of NaOH to moles of H2O using the stoichiometric ratio from the balanced equation:
1.25 moles NaOH x (2 moles H2O / 2 moles NaOH) = 1.25 moles H2O
Finally, we can convert moles of H2O to liters using the density of water:
1.25 moles H2O x (18.015 g/mol H2O) / (1000 g/L) = 0.0225 L H2O
Therefore, 50 g of NaOH will produce 0.0225 L or 22.5 mL of H2O.