Question

How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution?

find X and Y

Answer 1

Answer:Look at explanation

Explanation: Let X be the number of liters of the 20% alcohol solution to be added.

To find the resulting concentration when X liters of 20% alcohol solution are added to 40 liters of 50% alcohol solution, we can set up the following equation:

0.2X + 0.5(40) = 0.3(X + 40)

Simplifying and solving for X, we get:

0.2X + 20 = 0.3X + 12

0.1X = 8

X = 80

Therefore, 80 liters of the 20% alcohol solution should be added.

To check this answer, we can verify that the resulting solution will be 30% alcohol:

0.2(80) + 0.5(40) = 0.3(80 + 40)

16 + 20 = 36

So the resulting solution is indeed 30% alcohol.

Therefore, X = 80 liters and Y = 40 liters (the original amount of the 50% alcohol solution).