Question

A.005kg bullet going 200m/s, hits a .995kg block of wood, what is the final speed of the bullet and wood as they fly off together? ​

Answer 1

V= 1.9 m/s

Step-by-step explanation:

I did the test

Hope this helps :)

Answer 2

Given :

m 1 =0.5 kg

u 1 =0 m/s

m 2=0.005 kg

u 2=200 m/s

Let the velocity acquired by the block after the collision be V.

Using conservation of linear momentum before and after the collision : P i =P f

​∴ m1u 1 +m 2u 2=(m 1+m 2 )V

OR

0.5×0+0.005×200=(0.5+0.005)V

⟹V≈1.9 m/s