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Solve 2x 16 ≥ 32 - 6x.
-
A. xs-12
B. x≤ 6
C. x≥ 6
O D. xz-12

1 Answer

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Answer:


  • \mathrm{C.\;x\ge \:6}

Explanation:


\mathrm{2x-16\ge \:32-6x}

Add 16 to both sides:-


  • \mathrm{2x-16+16\ge \:32-6x+16}

  • \mathrm{2x\ge \:-6x+48}

Add 6x to both sides:-


  • \mathrm{2x+6x\ge \:-6x+48+6x}

  • \mathrm{8x\ge \:48}

Divide both sides by 8:-


  • \mathrm{\cfrac{8x}{8}\ge \cfrac{48}{8}}

  • \mathrm{x\ge \:6}

_______________________

Hope this helps!

User Oscar Bralo
by
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